hey guys, if i want to hook up a wideband to my interceptor gauge, is this kit all that'd be necessary?

http://cgi.ebay.com/ebaymotors/Innov...spagenameZWDVW

thanks!

 

Check your PM's

Edit:
Set your gauge to slope = 3, intercept = 7.4.

 

Share that **** w/ everyone Omega! I'm curious about swapping my stock boost gauge out w/ an interceptor and running the LC-1 to it...

 

thanks again, omega!

 

All I told him was about a local dealer, that would be better to buy from.... no boarder duties.
But I don't want to step on vendor toes.


Ok... to hook up the LC-1 to the Interceptor.. simply hook up one of the 5V signals to one of the analog ins (one of the outter pins).
In the settings, set the slope to 3, and the intercept to 7.4.
Done!

Edit:
My bad... you don't even have to hook up any ground wire... only the signal.

 

Sweet, thanks.

Does "simply hook up one of the 5V signals to one of the analog ins" mean that there are multiple inputs on the Interceptor?

Reason being, I would love to hook up an EGT as well, but I'm not sure if the Aeroforce has that capability...

 

each interceptor will have 2 anolog ins on it. I think anything with an analog 1-5v signal can be hooked to the interceptor

 

So... I remembered that you don't even have to hook up a ground.
The middle wire on the connector is the power supply.

Note, in this link the green and white wires are the analog in wire.
https://www.cobaltss.net/forums/show...ht=interceptor


Also, for those of you that have problems with the gauge being too bright... check out this link. There is a schematic at the bottom.
http://cosmicfoofoo.net/gaugepod/

 

Talk about reviving an old thread but i have a question. Does it matter if you put in 003.0 and 007.4 or is it --3.0 and --7.4

 

if you have an AEM UEGO gauge you can tap off of that to get the AFR on the interceptor. you connect the with wire from the uego to either analog 1 or 2 on the interceptor and set it up like this:

You know from the kit’s documentation that the output is
scaled such that 0v=10 A/F ratio, and 5v = 20 A/F ratio. The conversion
would then be a slope of 002.0, with an intercept of 010.0. In other words,
voltage multiplied by 2 plus 10 would equal A/F ratio. In this example, a
voltage of 5 would result in 5*2+10 equals 20 A/F ratio.

that is per the interceptor manual

 

Sorry i should have mentioned its an LC-1