Forced Induction Turbos/Superchargers

GTE Electric Supercharger??

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Old Jul 19, 2012 | 03:20 PM
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coltonbarrier's Avatar
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From: Davie
Question GTE Electric Supercharger??

Do the GTE Electric Superchargers work on cobalts?? And if so, would I need an extra battery to power it on an aftermarket alternator?
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Old Jul 19, 2012 | 03:31 PM
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they dont work on any car they are cheep crap and if anything will hinder the performance of your car because they will actauly restrict the air flow to the engine
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Old Jul 19, 2012 | 03:32 PM
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so even the gte will do that? I'm not talking about the cheap ebay ones. the ones that are like 200 bucks??
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Old Jul 19, 2012 | 03:34 PM
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not another one....
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Old Jul 19, 2012 | 03:34 PM
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OMG... its the same thing as the cheap ones just in a diferent plastic case with a biger price tag
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Old Jul 19, 2012 | 03:38 PM
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Works like a charm, GET IT.
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Old Jul 19, 2012 | 03:39 PM
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Old Jul 19, 2012 | 03:45 PM
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look I have seen what the manufacturer clames and I garintee its all crap take it from me generating 5 psi requires a substantual abount of power, note that the discription says "900 watts" this is obviously a lie want to know how I can tell? simple Watts=Voltag*Curent (aka amps) 900w/12v=75amps needed to make 900 wats now look at the little wires coming out of the device its about 10 or 12 gauge wire its really not posible to flow 75 amps through a 10 or 12 gauge wire look at amplifier installs amps with 75A requirements require 4-00 gauge wire (about the size of your finger or larger) understand? point number 2 when you generate that much power you also generate a bit of heat due to inefficiencies in the power consumption of the moter that kind of heatwould easily be enough to melt the cheap plastic of the device in question also dont forget that compressing air also generates a substantial amount of heat all of this makes it obvious that such a product is crap

Last edited by Axelthered05; Jul 21, 2012 at 11:23 AM.
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Old Jul 19, 2012 | 03:48 PM
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buy a gas powered leaf blower... thats been proven to pick up like 45hp on a civic on a dyno lol... google leaf blower dyno and youll see!
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Old Jul 19, 2012 | 03:53 PM
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^^yes i saw that and it was awesome lol
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Old Jul 20, 2012 | 12:06 AM
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Originally Posted by RoadconeTuning
buy a gas powered leaf blower... thats been proven to pick up like 45hp on a civic on a dyno lol... google leaf blower dyno and youll see!
I saw a twin leaf blower set up on an 80's corvette in a motortrend magazine lol actually had respectable gains for how ridiculous it looked
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Old Jul 20, 2012 | 11:54 AM
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lol I'm not thinking about buying one or anything im just curious...I do realize that they have all the cheap plastic crap ones. but i also just found a website selling them but there odl garrett turbos with electric motors on the back of them. heres the website xsturbos.com. They actually look very decent since there actual turbos converted. but idk if they work or not.
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Old Jul 20, 2012 | 06:00 PM
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Originally Posted by coltonbarrier
lol I'm not thinking about buying one or anything im just curious...I do realize that they have all the cheap plastic crap ones. but i also just found a website selling them but there odl garrett turbos with electric motors on the back of them. heres the website xsturbos.com. They actually look very decent since there actual turbos converted. but idk if they work or not.
*smacks forehead* no just no. look a turbo spins at ranges from 50000RPM to 125000RPM depending on the turbo in order to produce boost your not going to get that kind of speed from a motor especialy not from a $200 motor there using most electric motors range from 60-1000 rpm alone then if you use a gear box its posible to recah around 2-6k RPM but you have to remember that the more you gear up the rotations the more power is required then it goes right back to that hole paragraph a few posts back power and a bunch of other ****,

now granted those might get you a noticable gain but the likley hood of reaching any kind of boost above 2-3 psi is doubtfull

so I will be frank there is no easy/cheap way to go about forced induction eather do it right or dont do it

Last edited by Axelthered05; Jul 21, 2012 at 11:22 AM.
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Old Jul 20, 2012 | 06:05 PM
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Originally Posted by bluebalt07
I saw a twin leaf blower set up on an 80's corvette in a motortrend magazine lol actually had respectable gains for how ridiculous it looked
it was Hotrod, but yes. IIRC they made 1lb of boost with two 900CFm leaf blowers.

Edit: here is the story

http://www.hotrod.com/techarticles/e...r/viewall.html
http://www.hotrod.com/techarticles/e.../photo_09.html
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Old Jul 21, 2012 | 10:35 AM
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Originally Posted by LS6Rally
it was Hotrod, but yes. IIRC they made 1lb of boost with two 900CFm leaf blowers.

Edit: here is the story

Leaf Blower Supercharger - Hot Rod Magazine
Leaf Blower Supercharger Driving The New Corvette Hack Photo 9
Yep that's it lol for some reason I thought it was motortrend.
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Old Jul 21, 2012 | 10:53 AM
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Originally Posted by Axelthered05
look I have seen what the manufacturer clames and I garintee its all crap take it from an engineer generating 5 psi requires a substantual abount of power, note that the discription says "900 watts" this is obviously a lie want to know how I can tell? simple omes law Watts=Voltag*Curent (aka amps) 900w/12v=75amps needed to make 900 wats now look at the little wires coming out of the device its about 10 or 12 gauge wire its really not posible to flow 75 amps through a 10 or 12 gauge wire look at amplifier installs amps with 75A requirements require 4-00 gauge wire (about the size of your finger or larger) understand? point number 2 when you generate that much power you also generate a bit of heat due to inefficiencies in the power consumption of the moter that kind of heatwould easily be enough to melt the cheap plastic of the device in question also dont forget that compressing air also generates a substantial amount of heat all of this makes it obvious that such a product is crap
Ummm I just want to point out that this is completely wrong.

Ohm's Law: V = IR ; where V is voltage, I is current, and R is resistance.

Power: The rate of energy transfer. Measured in J/s (Joules per second) also known as Watts (named after James Watt). Simple UNIT CONVERSION will get you to watts from voltage, but not Ohm's Law

Voltage x Current = Power because voltage is a measure of J/C (Joules per Coulomb) and current is a measure of C/s (Coulombs per second). If you multiply them together the Coulombs cancel each other and you're left with J/s aka Watts.

I didn't do this to discredit you, just to correct the information that was put out there. Wouldn't want people basing there decision of whether or not to buy an electric supercharger off of incorrect data
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Old Jul 21, 2012 | 11:22 AM
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Originally Posted by Jdam8139
Ummm I just want to point out that this is completely wrong.

Ohm's Law: V = IR ; where V is voltage, I is current, and R is resistance.

Power: The rate of energy transfer. Measured in J/s (Joules per second) also known as Watts (named after James Watt). Simple UNIT CONVERSION will get you to watts from voltage, but not Ohm's Law

Voltage x Current = Power because voltage is a measure of J/C (Joules per Coulomb) and current is a measure of C/s (Coulombs per second). If you multiply them together the Coulombs cancel each other and you're left with J/s aka Watts.

I didn't do this to discredit you, just to correct the information that was put out there. Wouldn't want people basing there decision of whether or not to buy an electric supercharger off of incorrect data
actauly ohms law is I=V/R, V=IR is just a means of calculating the voltage after resistance using ohm's law. but you are esentauly corect I should not have called it ohms law excuse that mis lableing that was saposed to be the equation for watts but as long as the information is here to understand its meh I had originaly ment to explain that due to the resistance of a wire that small it could not sustain the needed curent to produce the 900W at 12v that is clamed by the manufacturer. trying to flow that much curent through a wire that small would cause the wire to eventauly fail due to the heat that is generated from the electrical resistance of the wire. you see the resistance does not change between the diferent amounts of curent. what changes is the amount of heet that is generated more curent=more heat. a larger wire has a lower resistance than a smaller wire which is why when you try to flow the same amount of curent through a small wire compared to a larger wire you generate to much heat in the smaller wire eventauly causing it to fail

Last edited by Axelthered05; Jul 21, 2012 at 11:53 AM.
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