think about this for a second
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From: Still fixing others mistakes.
Is your "proverbial" wall the 8g/sec max that can be put into HPT for IFR? I thought the flow rate modifier allowed us to get passed that. actually i see your talking about more precise control instead of just using a multiplier
maybe custom OS could extend some of the stock tables? Could the ecm handle even larger tables?
I think im way outta my league here. lol
maybe custom OS could extend some of the stock tables? Could the ecm handle even larger tables?
I think im way outta my league here. lol
if i was going to build a a lsj car. first thing i would do is rip the stock computer crap out of the car. wire up an hks vpro and make it a return style fuel system. then, the only limit is my wallet from then on out.
ANYWAYS. 275 hp per cylinder?
Last edited by Area47; Aug 31, 2007 at 11:53 AM. Reason: Automerged Doublepost
LSX RWD S/C conversion
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From: Maple Ridge, BC, Canada
If I understand the question correctly, the ecm OS is maxed at 64lb injectors, which is why we are going to a standalone.
I have been told that you can manipulate hpt by halfing all the values and raising them up again. I was also told for high HP that that option is "NOT" the way to go.
Yes, 275/cyl.
I have been told that you can manipulate hpt by halfing all the values and raising them up again. I was also told for high HP that that option is "NOT" the way to go.
Yes, 275/cyl.
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If I understand the question correctly, the ecm OS is maxed at 64lb injectors, which is why we are going to a standalone.
I have been told that you can manipulate hpt by halfing all the values and raising them up again. I was also told for high HP that that option is "NOT" the way to go.
Yes, 275/cyl.
I have been told that you can manipulate hpt by halfing all the values and raising them up again. I was also told for high HP that that option is "NOT" the way to go.
Yes, 275/cyl.
tested at 58 psi rail pressure
80% duty cycle
with a bsfc of .65
you're fuel requirements are 4 midgets with buckets
for stupid hp, the stock ecm needs to be junked
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one of the local skylines has 850cc injectors, and 1600cc injectors. the 850's run till about 5 psi. then at 6 psi, the 1600's kick in. three modified aeromotive a1000 pumps. one to the 850 rail, one to the 1600 rail, and one on the return side.
if one wants to make retarded power, one must have a retarded fuel supply
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your guess is as good as mine. im only factoring the injector vs crank hp. there is other factors in this game as well. im still figuring those up, but im stuck right now due to the actual flow volume of the stock pump.
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good sir!
one of the local skylines has 850cc injectors, and 1600cc injectors. the 850's run till about 5 psi. then at 6 psi, the 1600's kick in. three modified aeromotive a1000 pumps. one to the 850 rail, one to the 1600 rail, and one on the return side.
if one wants to make retarded power, one must have a retarded fuel supply
one of the local skylines has 850cc injectors, and 1600cc injectors. the 850's run till about 5 psi. then at 6 psi, the 1600's kick in. three modified aeromotive a1000 pumps. one to the 850 rail, one to the 1600 rail, and one on the return side.
if one wants to make retarded power, one must have a retarded fuel supply
The 4 midgets were not a problem.
Even the 4 large buckets, not a problem.
But now I need to find 4 retarded midgets and 4 retarded big buckets???
I give up
What you think of this Mr. Smart Guy?
N/A
4~(0%-10%) = total outcome * 1.5 / L
6~(0%-10%)= total outcome * 2 / L
8~(0%-10%)= total outcome * 3 / L
If X = total displacment, what is the total outcome of a 2.0l engine without force induction?
Force Induction (based on 80% effc.)
4~(0%-10%) = total outcome * 2.2 / L
6~(0%-10%)= total outcome * 2.6 / L
8~(0%-10%)= total outcome * 3.9 / L
If X = total displacment, what is the total outcome of a 2.0l engine with force induction (based on 80% effc.)?
N/A
4~(0%-10%) = total outcome * 1.5 / L
6~(0%-10%)= total outcome * 2 / L
8~(0%-10%)= total outcome * 3 / L
If X = total displacment, what is the total outcome of a 2.0l engine without force induction?
Force Induction (based on 80% effc.)
4~(0%-10%) = total outcome * 2.2 / L
6~(0%-10%)= total outcome * 2.6 / L
8~(0%-10%)= total outcome * 3.9 / L
If X = total displacment, what is the total outcome of a 2.0l engine with force induction (based on 80% effc.)?
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What you think of this Mr. Smart Guy?
N/A
4~(0%-10%) = total outcome * 1.5 / L
6~(0%-10%)= total outcome * 2 / L
8~(0%-10%)= total outcome * 3 / L
If X = total displacment, what is the total outcome of a 2.0l engine without force induction?
Force Induction (based on 80% effc.)
4~(0%-10%) = total outcome * 2.2 / L
6~(0%-10%)= total outcome * 2.6 / L
8~(0%-10%)= total outcome * 3.9 / L
If X = total displacment, what is the total outcome of a 2.0l engine with force induction (based on 80% effc.)?
N/A
4~(0%-10%) = total outcome * 1.5 / L
6~(0%-10%)= total outcome * 2 / L
8~(0%-10%)= total outcome * 3 / L
If X = total displacment, what is the total outcome of a 2.0l engine without force induction?
Force Induction (based on 80% effc.)
4~(0%-10%) = total outcome * 2.2 / L
6~(0%-10%)= total outcome * 2.6 / L
8~(0%-10%)= total outcome * 3.9 / L
If X = total displacment, what is the total outcome of a 2.0l engine with force induction (based on 80% effc.)?
AAAAAAAAHHHHHHHHHHHHHHHHHHHHHHHHHHHH
::smashes head into desk::
Last edited by Area47; Aug 31, 2007 at 01:20 PM. Reason: Automerged Doublepost
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